document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1154858>Question 1154858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Find the equation of the line tangent to the following curve at the given value of x. Y=2sinxcosx; x=pi/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777378 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line tangent to the following curve at the given value of x. Y=2sinxcosx; x=pi/4<BR>\n" );
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document.write( "Y=2sin(x)cos(x)<BR>\n" );
document.write( "y = sin(2x)<BR>\n" );
document.write( "y' = 2cos(2x)<BR>\n" );
document.write( "---> 2cos(pi/2)<BR>\n" );
document.write( "--> slope = 0<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Equation of the line tangent is y = 1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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