document.write( "Question 1154864: If two construction teams work together, they can finish a road in 15 days. The rate of work of the first team is 4/5 of the rate of the second team. \r
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Algebra.Com's Answer #777376 by VFBundy(438)\"\" \"About 
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Rate of work of first team = \"%284%2F5%29%281%2Fx%29\" = \"4%2F5x\"
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\n" ); document.write( "Rate of work working together = \"%284%2F5x%29+%2B+%281%2Fx%29\" = \"1%2F15\" --> \"%284%2F5x%29+%2B+%285%2F5x%29\" = \"1%2F15\" --> \"%289%2F5x%29\" = \"1%2F15\" --> \"5x+=+135\" --> \"x+=++27\"
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\n" ); document.write( "Plug in x = 27:
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\n" ); document.write( "Rate of work of first team = \"%284%2F5%29%281%2Fx%29\" = \"4%2F5x\" = \"4%2F135\"
\n" ); document.write( "Rate of work of second team = \"1%2Fx\" = \"1%2F27\"
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\n" ); document.write( "Since the first team completes 4/135 of the job per day, this means it will take them 135/4 days...or 33.75 days...to complete the job working alone.
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\n" ); document.write( "Since the second team completes 1/27 of the job per day, this means it will take them 27 days to complete the job working alone.
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