document.write( "Question 1154864: If two construction teams work together, they can finish a road in 15 days. The rate of work of the first team is 4/5 of the rate of the second team. \r
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Algebra.Com's Answer #777373 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If two construction teams work together they can finish a road in 15 days.the rate of work of the first team is 4/5 of the rate of the second team.
\n" ); document.write( "How many days each team needs to complete this job alone. \r
\n" ); document.write( "\n" ); document.write( "Let one team take x hours to do the job\r
\n" ); document.write( "\n" ); document.write( "This team does 1/x of the job in 1 hour alone\r
\n" ); document.write( "\n" ); document.write( "They take (4/5)x hours to do the job
\n" ); document.write( "This team does (5/4x) of the job in 1 hour alone\r
\n" ); document.write( "\n" ); document.write( "Both together do the job in 15 days
\n" ); document.write( "Together the complete 1/15 of the job in1 hour\r
\n" ); document.write( "\n" ); document.write( "\"+1%2Fx+%2B%285%2F4x%29+=+1%2F15\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%289%2F4x%29=1%2F15+\"\r
\n" ); document.write( "\n" ); document.write( "4x = 135
\n" ); document.write( "x =135/4
\n" ); document.write( "x =33.75
\n" ); document.write( "First team 33.75 days
\n" ); document.write( "II team
\n" ); document.write( "(4/5)*33.75 =27 days \r
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