document.write( "Question 1154821: What are all the zeroes for 2x^4 + 13x^3 + 22x^2 + 8x = 0 if -2 is one of the zeroes? \n" ); document.write( "

Algebra.Com's Answer #777310 by Edwin McCravy(20055) $\"\"$ $\"About$

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document.write( "We can factor out x\r\n" );
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document.write( "Since -2 is one of its zeros, the polynomial in parentheses must be divisible by\r\n" );
document.write( "(x+2) because (x+2) would have to be one of the factors that you'd have to set\r\n" );
document.write( "equal to zero in order to get x = -2.  We'll use synthetic division\r\n" );
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document.write( "-2|2 13  22  8  \r\n" );
document.write( "  |  -4 -18 -8  \r\n" );
document.write( "   2  9   4  0  \r\n" );
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document.write( "So we have factored the left side of the polynomial equation as\r\n" );
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document.write( "We can factor further as\r\n" );
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document.write( "Use the zero-factor property:\r\n" );
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document.write( "x=0;   x+2=0;    x+4=0;     2x+1=0\r\n" );
document.write( "         x=-2      x=-4;      2x=-1\r\n" );
document.write( "                               x=-1/2\r\n" );
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document.write( "The four zeros are 0; -2; -4; -1/2\r\n" );
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document.write( "Edwin

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