document.write( "Question 1154772: To the nearest tenth of a degree, calculate the angles of the triangle with vertices (0, 0), (6, 3), and (1, 8). \n" ); document.write( "
Algebra.Com's Answer #777262 by VFBundy(438)\"\" \"About 
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\n" ); document.write( "Use the Law of Cosines:
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\n" ); document.write( "C² = A² + B² - 2AB(cos c)
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\n" ); document.write( "\"sqrt%2865%29%5E2\" = \"sqrt%2850%29%5E2+%2B+sqrt%2845%29%5E2+-+2sqrt%2850%29sqrt%2845%29%28cos%28c%29%29\"
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\n" ); document.write( "\"65\" = \"50+%2B+45+-+2sqrt%282250%29%28cos%28c%29%29\"
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\n" ); document.write( "\"65\" = \"95+-+2sqrt%282250%29%28cos%28c%29%29\"
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\n" ); document.write( "\"-30\" = \"-2sqrt%282250%29%28cos%28c%29%29\"
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\n" ); document.write( "\"15\" = \"sqrt%282250%29%28cos%28c%29%29\"
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\n" ); document.write( "\"15%2Fsqrt%282250%29\" = \"cos%28c%29\"
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\n" ); document.write( "\"cos%28c%29\" = \"0.3162\"
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\n" ); document.write( "\"c\" = \"arccos%280.3162%29\"
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\n" ); document.write( "c = 1.2491
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\n" ); document.write( "Now, use the Law of Sines:
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\n" ); document.write( "\"b%2Fsqrt%2845%29\" = \"c%2Fsqrt%2865%29\"
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\n" ); document.write( "\"b%2Fsqrt%2845%29\" = \"1.2491%2Fsqrt%2865%29\"
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\n" ); document.write( "Cross-multiply:
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\n" ); document.write( "\"b%2Asqrt%2865%29\" = \"1.2491%2Asqrt%2845%29\"
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\n" ); document.write( "\"b%2Asqrt%2865%29\" = \"8.3792\"
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\n" ); document.write( "\"b\" = \"8.3792%2Fsqrt%2865%29\"
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\n" ); document.write( "b = 1.0393
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\n" ); document.write( "So, we know b = 1.0393 radians. This is 59.6 degrees. We also know c = 1.2491 radians. This is 71.6 degrees.
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\n" ); document.write( "Subtracting both these numbers from 180 degrees, this means a = 48.8 degrees.
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\n" ); document.write( "In summary:
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\n" ); document.write( "a = 48.8 degrees
\n" ); document.write( "b = 59.6 degrees
\n" ); document.write( "c = 71.6 degrees
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