document.write( "Question 1154775: The sides of a square are parallel to the coordinate axes. Its vertices lie on the circle of radius 5 whose center is at the origin. Find coordinates for the four vertices of this square. \n" ); document.write( "

Algebra.Com's Answer #777261 by Edwin McCravy(20063) $\"\"$ $\"About$

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Let the coordinates of the four vertices be (-x,x), (-x,-x), (x,-x), and (x,x). \r\n" );
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document.write( "Draw a radius (in green) from the origin (0,0) to a corner of the \r\n" );
document.write( "square. That makes an isosceles right triangle with hypotenuse\r\n" );
document.write( "the green line, which is 5, since it is a radius of the circle.\r\n" );
document.write( "Let the legs of the isosceles right triangle be x each.\r\n" );
document.write( "We apply the Pythagorean theorem to the isosceles right triangle:\r\n" );
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document.write( "So the coordinates of the vertices are:\r\n" );
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document.write( ",,,\r\n" );
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document.write( "Edwin

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