document.write( "Question 1154751: Please help me answer this question:\r
\n" ); document.write( "\n" ); document.write( "The intensity level of a sound produced by a machine is increased by 5dB. Will the new intensity of the sound be 5 times the original? Explain your answer. \n" ); document.write( "

Algebra.Com's Answer #777253 by math_helper(2461) $\"\"$ $\"About$

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document.write( "Sound intensity in dB = 10log(I/Io)\r
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document.write( "where   Io = threshold of hearing (about  W/m^2)\r
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document.write( "   5dB = 10log(I/Io)
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document.write( "   5/10 = log(I/Io)
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document.write( "   10^(5/10) = I/Io
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document.write( "    3.16  = I/Io    <<<< The sound intensity will be 3.16 times the original.\r
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document.write( "The rule of thumb when dealing with measurements in dB is this:
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document.write( "For every 3dB increase, you approximately double the intensity.
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document.write( "For every 3dB decrease, you approximately halve the intensity.\r
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document.write( "This comes from  3dB=10log(I/Io) ==> I/Io = 10^(3/10) = (approx) 1.9953\r
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