document.write( "Question 1154724: Alex is 3 years older than Sophia. In 9 years the sum of their ages will be 55. How old is Alex now?
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Algebra.Com's Answer #777202 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "A = Alex's current age
\n" ); document.write( "S = Sophia's current age\r
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\n" ); document.write( "\n" ); document.write( "Right now, Alex is 3 years older than Sophia.
\n" ); document.write( "We add 3 years to Sophia's age (S) to get Alex's age (A)
\n" ); document.write( "A = S+3
\n" ); document.write( "This equation will hold true for past and future ages as well.\r
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\n" ); document.write( "\n" ); document.write( "Let's fast-forward into the future.
\n" ); document.write( "A+9 = Alex's age 9 years from now
\n" ); document.write( "S+9 = Sophia's age 9 years from now
\n" ); document.write( "Those two expressions sum to
\n" ); document.write( "(A+9)+(S+9) = A+S+18
\n" ); document.write( "and we are told this is equal to 55
\n" ); document.write( "A+S+18 = 55\r
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\n" ); document.write( "\n" ); document.write( "Plug in A = S+3 and solve for S\r
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\n" ); document.write( "\n" ); document.write( "A+S+18 = 55
\n" ); document.write( "S+3+S+18 = 55 ... wherever you see an 'A\", replace with 'S+3'
\n" ); document.write( "2S+21 = 55
\n" ); document.write( "2S+21-21 = 55-21 .... subtract 21 from both sides
\n" ); document.write( "2S = 34
\n" ); document.write( "2S/2 = 34/2 ... divide both sides by 2
\n" ); document.write( "S = 17
\n" ); document.write( "Currently, Sophia is 17 years old\r
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\n" ); document.write( "\n" ); document.write( "Use her current age to find Alex's current age
\n" ); document.write( "A = S+3
\n" ); document.write( "A = 17+3
\n" ); document.write( "A = 20\r
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\n" ); document.write( "\n" ); document.write( "Answer: Alex is currently 20 years old\r
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