document.write( "Question 106807: I have this question, but I'm not sure how to solve it because it is cubed, I'm pretty sure its squared but I still dont know how to solve it. Someone please help me, thank you!! \r
\n" ); document.write( "\n" ); document.write( "Find the inverse for \"+f%28x%29+=+x%5E3%2B1+\" , and verify that the functions are inverses of each other.
\n" ); document.write( "

Algebra.Com's Answer #77719 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Find the inverse and verify:
\n" ); document.write( "\"f%28x%29+=+x%5E3%2B1\" Change the f(x) to y, then interchange the x and y.
\n" ); document.write( "\"y+=+x%5E3%2B1\"
\n" ); document.write( "\"x+=+y%5E3%2B1\" Now solve this for y.
\n" ); document.write( "\"y%5E3+=+x-1\" Take the cube root of both sides.
\n" ); document.write( "\"y+=+%28x-1%29%5E%281%2F3%29\" Now change the y to \"f%5E%28-1%29%28x%29\".
\n" ); document.write( "\"f%5E%28-1%29%28x%29+=+%28x-1%29%5E%281%2F3%29\"
\n" ); document.write( "Check:
\n" ); document.write( "Show that \"f%28f%5E%28-1%29%28x%29%29+=+x\"
\n" ); document.write( "\"f%28f%5E%28-1%29%28x%29%29+=+f%28%28x-1%29%5E%281%2F3%29%29\" = \"%28%28x-1%29%5E%281%2F3%29%29%5E3%2B1+=+%28x-1%29%2B1\" = x
\n" ); document.write( "
\n" );