document.write( "Question 1154707: In drawing of two cards in a standard deck one at a
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Algebra.Com's Answer #777187 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Since you are given that you did not draw a king on the first draw,\r\n" );
document.write( "then you are given that you have a deck of 51 which contains all\r\n" );
document.write( "4 kings and 51-4-47 non-kings. So the probability that you will get a\r\n" );
document.write( "non-king on your second draw is 47 ways out of 51, or a probability of\r\n" );
document.write( "47/51, approximately 92% of the time.\r\n" );
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document.write( "Answer: 47/51.\r\n" );
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document.write( "Edwin

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