document.write( "Question 106801: This one boggles my mind!
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document.write( "One number is 2 less than another. If 9 times the smaller number minus 2 times the larger number is 52, find the two numbers.\r
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Algebra.Com's Answer #77715 by Earlsdon(6294) ![]() You can put this solution on YOUR website! Let's see if we can unboggle your mind. \n" ); document.write( "Let the smaller number be x and the larger number be y. \n" ); document.write( "x = y-2 \"One number is 2 less than another number\" \n" ); document.write( "9x-2y = 52 \"...9 times the smaller number minus 2 times the larger number is 52\" \n" ); document.write( "Substitute the x = y-2 into the second equation and solve for y. \n" ); document.write( "9(y-2)-2y = 52 Simplify. \n" ); document.write( "9y-18-2y = 52 \n" ); document.write( "7y-18 = 52 Add 18 to both sides. \n" ); document.write( "7y = 70 Divide both sides by 7. \n" ); document.write( "y = 10 ...and \n" ); document.write( "x = y-2 \n" ); document.write( "x = 10-2 \n" ); document.write( "x = 8\r \n" ); document.write( "\n" ); document.write( "The two numbers are: 8 and 10\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "x = y-2 \n" ); document.write( "8 = 10-2 \n" ); document.write( "8 = 8 \n" ); document.write( "9x-2y = 52 \n" ); document.write( "9(8)-2(10) = 52 \n" ); document.write( "72 - 20 = 52 \n" ); document.write( "52 = 52 \n" ); document.write( " |