document.write( "Question 1154666: Hi\r
\n" ); document.write( "\n" ); document.write( "A person covers 2/3 of his journey at his usual speed and the remaining distance at 3/4 of the usual speed and takes 30min more than the usual time. If total distance is 180km what is the usual speed. \r
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Algebra.Com's Answer #777143 by ikleyn(52848)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "It is clear that we can exclude the first 2/3 of the journey from the consideration,\r\n" );
document.write( "since at this part there is no delay comparing with the standard schedule.\r\n" );
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document.write( "The difference arises on the remained 1/3 distance, which is 60 miles.\r\n" );
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document.write( "For this part of 60 miles, we have a regular time  \"60%2Fx\", where x is the regular speed.\r\n" );
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document.write( "With the speed of \"%283%2F4%29x\", the spent time is  \"60%2F%28%283%2F4%29x%29\" = \"80%2Fx\".\r\n" );
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document.write( "So, the delay equation is\r\n" );
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document.write( "    \"80%2Fx\" - \"60%2Fx\" = \"1%2F2\"   (which is half of an hour)\r\n" );
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document.write( "From the equation,  \r\n" );
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document.write( "    \"20%2Fx\" = \"1%2F2\";\r\n" );
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document.write( "hence,\r\n" );
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document.write( "    x = \"20%2F%28%281%2F2%29%29\" = 2*20 = 40 kilometers per hour.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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