document.write( "Question 1154666: Hi\r
\n" ); document.write( "\n" ); document.write( "A person covers 2/3 of his journey at his usual speed and the remaining distance at 3/4 of the usual speed and takes 30min more than the usual time. If total distance is 180km what is the usual speed. \r
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Algebra.Com's Answer #777137 by mananth(16946)\"\" \"About 
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\n" ); document.write( "A person covers 2/3 of his journey at his usual speed and the remaining distance at 3/4 of the usual speed and takes 30min more than the usual time. If total distance is 180km what is the usual speed. \r
\n" ); document.write( "\n" ); document.write( "2/3 * 180 =120\r
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\n" ); document.write( "\n" ); document.write( "let the usual speed be x km/h
\n" ); document.write( "distance 120 km
\n" ); document.write( "time = 120/x First part \r
\n" ); document.write( "\n" ); document.write( "distance = 60 km
\n" ); document.write( "speed = 3x/4\r
\n" ); document.write( "\n" ); document.write( "Time taken = 60/(3x/4)\r
\n" ); document.write( "\n" ); document.write( "=240/3x
\n" ); document.write( "=80/x II part\r
\n" ); document.write( "\n" ); document.write( "120/x +80/x = 180/x + 1/2 ( 30 minutes =1/2)\r
\n" ); document.write( "\n" ); document.write( "200/x = 180/x +1/2\r
\n" ); document.write( "\n" ); document.write( "20/x = 1/2\r
\n" ); document.write( "\n" ); document.write( "x= 40 km/h\r
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