Algebra.Com's Answer #777136 by ikleyn(52784)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
.
\n" );
document.write( "suppose you just received a shipment of ten televisions. four of the televisions are defective.
\n" );
document.write( "(a) if two televisions are randomly selected, compute the probability that both televisions work.
\n" );
document.write( "(b) what is the probability that at least one of the two televisions don’t work?
\n" );
document.write( "~~~~~~~~~~~~~~~~~~~\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "\r\n" );
document.write( "(a) The probability in case (a) can be computed in two ways.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " First way is P =  =  =  .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " Explanation. \r\n" );
document.write( "\r\n" );
document.write( " The probability to select 1-st TV proper is  ; the probability to select 2-nd TV proper is  .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " Second way is P =  =  =  = , giving the same answer.\r\n" );
document.write( "\r\n" );
document.write( " Explanation. \r\n" );
document.write( "\r\n" );
document.write( " The denominator is the number of all pairs of 10 TVs; the numerator is the number of all pairs of proper TVs.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b) The probability in this case is the complement to the probability of case (a), i.e.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " P = 1 - =  .\r\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( " |