document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1154616>Question 1154616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 20.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777116 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your regular polygon would be an equilateral triangle.  It is composed on six special 30-60-90 congruent triangles, each having a short leg of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"10%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.   You should be able to use that to find the area of your figure. </SPAN>\n" );
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