document.write( "Question 1154642: The fifth term of an arithmetic sequence is 41 and the twelfth term is 20. Determine the 100th term of the sequence \n" ); document.write( "
Algebra.Com's Answer #777115 by josgarithmetic(39618)\"\" \"About 
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Seven differences to go from 41 to 20.\r
\n" ); document.write( "\n" ); document.write( "\"20-41=-21\"\r
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\n" ); document.write( "\n" ); document.write( "\"-21%2F7=-3\"\r
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\n" ); document.write( "\n" ); document.write( "If term #1 is \"A%5B1%5D\", then \"A%5B1%5D%2B%28-3%29%285-1%29=41\".\r
\n" ); document.write( "\n" ); document.write( "Find this term #1, \"A%5B1%5D\".
\n" ); document.write( "Use that to answer your exercise's question.
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