document.write( "Question 1154519: Given: Parallelogram FRED, AF ≅ DF , R 124°
\n" ); document.write( "Find : m∠AFD \n" ); document.write( "

Algebra.Com's Answer #776953 by MathLover1(20855) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "If $\"m\"$ < $\"R+=+124\"$ °, what is $\"m\"$ < $\"AFD\"$ ?\r
\n" ); document.write( "\n" ); document.write( " $\"m\"$ < $\"R+=+124\"$ °, measure of its opposite angle is same, so $\"m\"$ ∠ $\"D+=+124\"$ °\r
\n" ); document.write( "\n" ); document.write( "triangle $\"AFD\"$ lies between parallel lines, so sides $\"AF+\"$ and $\"FD\"$ are equal in length\r
\n" ); document.write( "\n" ); document.write( "since $\"m\"$ < $\"D+=+124\"$ ° and $\"+AF=FD\"$ , measure of angles at $\"A+\"$ and $\"D\"$ in triangle $\"AFD\"$ are $\"180-124=56\"$ °\r
\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( " $\"m\"$ < $\"AFD=180-%2856%2B56%29\"$
\n" ); document.write( " $\"m\"$ < $\"AFD=180-112\"$
\n" ); document.write( " $\"m\"$ < $\"AFD=68\"$ °\r
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