document.write( "Question 1154438: A charter flight charges a fare of​ $300 per person plus ​$6 per person for each unsold seat on the plane. If the plane holds 100 passengers and if x represents the number of unsold​ seats, find the following.\r
\n" ); document.write( "\n" ); document.write( "A. An expression for the total revenue received for the flight. ​(Hint​: Multiply the number of people​ flying, 100-​x, by the price per​ ticket.)\r
\n" ); document.write( "\n" ); document.write( "B. The number of unsold seats that will produce the maximum revenue.\r
\n" ); document.write( "\n" ); document.write( "C.The maximum revenue.
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Algebra.Com's Answer #776889 by ankor@dixie-net.com(22740)\"\" \"About 
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A charter flight charges a fare of​ $300 per person plus ​$6 per person for each unsold seat on the plane.
\n" ); document.write( " If the plane holds 100 passengers and if x represents the number of unsold​ seats, find the following.
\n" ); document.write( ":
\n" ); document.write( "A. An expression for the total revenue received for the flight. ​(Hint​: Multiply the number of people​ flying, 100-​x, by the price per​ ticket.
\n" ); document.write( "total cost = cost per seat * no. of seats sold
\n" ); document.write( "f(x) = (300+6x)*(100-x)
\n" ); document.write( "FOIL
\n" ); document.write( "f(x) = 30000 - 300x + 600x - 6x^2
\n" ); document.write( "f(x) = -6x^2 + 300x + 30000; is the revenue equation
\n" ); document.write( ":
\n" ); document.write( "B. The number of unsold seats that will produce the maximum revenue.
\n" ); document.write( "Max will be on the axis of symmetry; x = -b/(2a), a=-6; b=300
\n" ); document.write( "x = \"%28-300%29%2F%282%2A-6%29\"
\n" ); document.write( "x = 25 seats unsold
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\n" ); document.write( "C.The maximum revenue.
\n" ); document.write( "no. of seats sold: 100-25 = 75
\n" ); document.write( "seat cost: 300 + 6(25) = $450
\n" ); document.write( "therefore
\n" ); document.write( "75 * 450 = $33,750 is max revenue
\n" ); document.write( ":
\n" ); document.write( "Note: you can also substitute 25 for x in the original equation to get the max revenue
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