document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106753>Question 106753</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/188514590x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> According to the U.S. Census Bureau the population of the United States has been growing at an average of approximately 2% per year. The census is taken every 10 years and the population in 1980 was estimated at 226 million people\r<BR>\n" );
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document.write( "c)   If the rate of population growth in the U.S. were to continue at about 2%, in about what year would the population in the United States reach and surpass one billion? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77683 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> According to the U.S. Census Bureau the population of the United States has been growing at an average of approximately 2% per year. The census is taken every 10 years and the population in 1980 was estimated at 226 million people\r<BR>\n" );
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document.write( "Let \"x\" be the number of years after 1980<BR>\n" );
document.write( "P(x) = 226(1.02)^x million people<BR>\n" );
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document.write( "c) If the rate of population growth in the U.S. were to continue at about 2%, in about what year would the population in the United States reach and surpass one billion?<BR>\n" );
document.write( "10^9 = 226x10^6(1.02)^x<BR>\n" );
document.write( "1.02^x = 10^3/226= <BR>\n" );
document.write( "x(log(1.02)) = log(10^3)-(log(226)<BR>\n" );
document.write( "x(log1.02) = 0.645891561...<BR>\n" );
document.write( "x = 75.10..<BR>\n" );
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document.write( "1 billion would be reached in 1980+75.10= 2055.10<BR>\n" );
document.write( "or in the year 2056<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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