document.write( "Question 1154396: Lucy is going to invest $10,000 and leave it in an account for 13 years. Assuming the interest is compounded continuously, what interest rate, to the nearest tenth of a percent, would be required in order for Lucy to end up with $13,000? \n" ); document.write( "

Algebra.Com's Answer #776827 by ikleyn(52792) $\"\"$ $\"About$

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document.write( "13000 = \r\n" );
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document.write( " = \r\n" );
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document.write( "1.3 = \r\n" );
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document.write( "Take the natural logarithm from both sides\r\n" );
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document.write( "ln(1.3) = 13t\r\n" );
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document.write( "t =  = 0.020182 = 2.018%.      ANSWER\r\n" );
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