document.write( "Question 1154273: Parallelogram PQRS has PQ = 8 cm, QR = 9 cm, and diagonal QS = 10 cm. Mark F on RS, exactly 5 cm from S. Let T be the intersection of PF and QS. Find the lengths TS and TQ. \n" ); document.write( "
Algebra.Com's Answer #776794 by Edwin McCravy(20055)\"\" \"About 
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document.write( "ΔFST ∽ ΔPQT\r\n" );
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document.write( "\"%28PQ%29%2F%28FS%29=%28TQ%29%2F%28TS%29\"\r\n" );
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document.write( "\"%288%29%2F%285%29=%28TQ%29%2F%28TS%29\"\r\n" );
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document.write( "\"TS+%2B+TQ+=+QS+=+8\"\r\n" );
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document.write( "\"TS+%2B+TQ+=+8\"\r\n" );
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document.write( "\"TQ+=+8-TS\"\r\n" );
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document.write( "\"%288%29%2F%285%29=%288-TS%29%2FTS\"\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "\"8%2ATS=5%288-TS%29\"\r\n" );
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document.write( "Distribute:\r\n" );
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document.write( "\"8%2ATS=40-5%2ATS\"\r\n" );
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document.write( "\"13%2ATS=40\"\r\n" );
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document.write( "\"TS=40%2F13\"\r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "\"TQ+=+8-TS\"\r\n" );
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document.write( "\"TQ+=+8-40%2F13\"\r\n" );
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document.write( "Get LCD\r\n" );
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document.write( "\"TQ+=+104%2F13-40%2F13\"\r\n" );
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document.write( "\"TQ=64%2F13\"\r\n" );
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document.write( "Answer: \r\n" );
document.write( "\"TQ=64%2F13=4%2612%2F13\"\r\n" );
document.write( "\"TS=40%2F13=3%261%2F13\"\r\n" );
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document.write( "Edwin
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