document.write( "Question 1154331: Susan keeps track of the number of tickets sold for each play presented at The Community Theater. The mean of her data is 117, and the standard deviation is 47. Within how many standard deviations of the mean do all the values fall? Data: 59, 143, 80, 69, 176, 86, 160, 65, 152, 184 *
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Algebra.Com's Answer #776779 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Original set = {59, 143, 80, 69, 176, 86, 160, 65, 152, 184}
\n" ); document.write( "Sorted set = {59, 65, 69, 80, 86, 143, 152, 160, 176, 184}
\n" ); document.write( "min = 59 and max = 184\r
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\n" ); document.write( "\n" ); document.write( "mu = mean = 117
\n" ); document.write( "sigma = standard deviation = 47\r
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\n" ); document.write( "\n" ); document.write( "1 standard deviation from the mean
\n" ); document.write( "L = lower bound = mu - 1*sigma = 117-1*47 = 70
\n" ); document.write( "U = upper bound = mu + 1*sigma = 117+1*47 = 164\r
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\n" ); document.write( "\n" ); document.write( "Ask yourself: Do all of the data values fall within the interval \"70+%3C=+x+%3C=+164\" (this is in the form \"L+%3C=+x+%3C=+U\")? The answer is 'no' because 59, 65, 69, 176, and 184 are outside this range.\r
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\n" ); document.write( "\n" ); document.write( "2 standard deviations from the mean
\n" ); document.write( "L = lower bound = mu - 2*sigma = 117-2*47 = 23
\n" ); document.write( "U = upper bound = mu + 2*sigma = 117+2*47 = 211\r
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\n" ); document.write( "\n" ); document.write( "The interval is now \"23+%3C=+x+%3C=+211\". Ask a similar question: Do all of the data values fall within the range \"23+%3C=+x+%3C=+211\"? The answer is 'yes'. This is because L = 23 is smaller than the min = 59, while U = 211 is larger than the max = 184.\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: 2 standard deviations
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