document.write( "Question 106663: Bob invested $21,000, part at 18% and part at 8%. If the total interest at the end of the year is $1,980, how much did he invest at 18%? \n" ); document.write( "
Algebra.Com's Answer #77675 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! Bob invested $21,000, part at 18% and part at 8%. If the total interest at the end of the year is $1,980, how much did he invest at 18%? \n" ); document.write( "x+y=21000 \n" ); document.write( ".18x+.08y=1980 \n" ); document.write( "------------------------ \n" ); document.write( "x=21000-y \n" ); document.write( ".18(21000-y)+.08y=1980 \n" ); document.write( "3780-.18y+.08y=1980 \n" ); document.write( "-.1y=-1800 \n" ); document.write( "y=18000 \n" ); document.write( "------------ \n" ); document.write( "x+18000=21000 \n" ); document.write( "x=3000 \n" ); document.write( "------------------ \n" ); document.write( "so he invested $3000 at 18% \n" ); document.write( ":) \n" ); document.write( " |