document.write( "Question 106663: Bob invested $21,000, part at 18% and part at 8%. If the total interest at the end of the year is $1,980, how much did he invest at 18%? \n" ); document.write( "
Algebra.Com's Answer #77675 by elima(1433)\"\" \"About 
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Bob invested $21,000, part at 18% and part at 8%. If the total interest at the end of the year is $1,980, how much did he invest at 18%?
\n" ); document.write( "x+y=21000
\n" ); document.write( ".18x+.08y=1980
\n" ); document.write( "------------------------
\n" ); document.write( "x=21000-y
\n" ); document.write( ".18(21000-y)+.08y=1980
\n" ); document.write( "3780-.18y+.08y=1980
\n" ); document.write( "-.1y=-1800
\n" ); document.write( "y=18000
\n" ); document.write( "------------
\n" ); document.write( "x+18000=21000
\n" ); document.write( "x=3000
\n" ); document.write( "------------------
\n" ); document.write( "so he invested $3000 at 18%
\n" ); document.write( ":)
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