document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1154329>Question 1154329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A vessel has a shape of a right circular cone with a depth of 33 cm and a top diameter 22 cm. The vessel contains liquid to a depth of 15 cm. How many more litres of liquid needs to be added in order to fill the vessel?\r<BR>\n" );
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document.write( "Round to one decimal place. \r<BR>\n" );
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document.write( "please help me solve it <BR>\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #776724 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=776724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=mananth&illustration_name=frustum1.png\">.<BR>\n" );
document.write( "Volume of Frustum of a cone = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%2Ah%2F3%29%28R%5E2%2Br%5E2%2BrR%29 ALIGN=MIDDLE  ALT=\"%28pi%2Ah%2F3%29%28R%5E2%2Br%5E2%2BrR%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "here R =11, r=5, h=18 \r<BR>\n" );
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document.write( "plug values<BR>\n" );
document.write( "(6*pi)*(11^2+5^2+55) =3789 cm^3\r<BR>\n" );
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document.write( "1 liter = 1000 cm^3\r<BR>\n" );
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document.write( "3,789 liters is required </SPAN>\n" );
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