document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106662>Question 106662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 less than another.  If 10 times the smaller number minus 3 times the larger number is 51, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77672 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 4 less than another.  If 10 times the smaller number minus 3 times the larger number is 51, find the two numbers.<BR>\n" );
document.write( "x=y-4<BR>\n" );
document.write( "10x-3y=51<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "10(y-4)-3y=51<BR>\n" );
document.write( "10y-40-3y=51<BR>\n" );
document.write( "7y=51+40<BR>\n" );
document.write( "7y=91<BR>\n" );
document.write( "y=13<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "x=13-4<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );