document.write( "Question 1154228: adult tickets cost 8$ and student tickets for the concert cost 4$ exactly 290 tickets were sold and there was 1,440 made total how many students and adults tickets were sold \n" ); document.write( "
Algebra.Com's Answer #776627 by greenestamps(13367)\"\" \"About 
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\n" ); document.write( "Formally....

\n" ); document.write( "a = number of adult tickets
\n" ); document.write( "s = number of student tickets

\n" ); document.write( "a+s = 290 (the total number of tickets was 290)
\n" ); document.write( "8a+4s = 1440 (the total cost, at $8 per adult and $4 per student, was $1440)

\n" ); document.write( "Solve the pair of equations by your favorite method....

\n" ); document.write( "When the equations are both in that form, elimination is easiest.

\n" ); document.write( "4a+4s = 1160
\n" ); document.write( "8a+4s = 1440

\n" ); document.write( "subtract one equation from the other to eliminate s

\n" ); document.write( "4a = 280
\n" ); document.write( "a = 70

\n" ); document.write( "There were 70 adult tickets.

\n" ); document.write( "So there were 290-70 = 220 student tickets.

\n" ); document.write( "ANSWER: 70 adult tickets, 220 student tickets.

\n" ); document.write( "CHECK: 70(8)+220(4) = 560+880 = 1440

\n" ); document.write( "Informally -- if an algebraic solution is not required....

\n" ); document.write( "(1) If all 290 tickets had been student tickets, the total cost would have been $290*4 = $1160; the actual total is $1440-$1160 = $280 more than that.
\n" ); document.write( "(2) The difference between the cost of an adult ticket and a student ticket is $4.
\n" ); document.write( "(3) The number of adult tickets needed to make up that extra $280 is 280/4 = 70.

\n" ); document.write( "ANSWER: 70 adult tickets and 220 student tickets

\n" ); document.write( "Note that the informal solution used exactly the same calculations as the formal method....

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