document.write( "Question 1154228: adult tickets cost 8$ and student tickets for the concert cost 4$ exactly 290 tickets were sold and there was 1,440 made total how many students and adults tickets were sold \n" ); document.write( "
Algebra.Com's Answer #776627 by greenestamps(13367) You can put this solution on YOUR website! \n" ); document.write( "Formally.... \n" ); document.write( "a = number of adult tickets \n" ); document.write( "s = number of student tickets \n" ); document.write( "a+s = 290 (the total number of tickets was 290) \n" ); document.write( "8a+4s = 1440 (the total cost, at $8 per adult and $4 per student, was $1440) \n" ); document.write( "Solve the pair of equations by your favorite method.... \n" ); document.write( "When the equations are both in that form, elimination is easiest. \n" ); document.write( "4a+4s = 1160 \n" ); document.write( "8a+4s = 1440 \n" ); document.write( "subtract one equation from the other to eliminate s \n" ); document.write( "4a = 280 \n" ); document.write( "a = 70 \n" ); document.write( "There were 70 adult tickets. \n" ); document.write( "So there were 290-70 = 220 student tickets. \n" ); document.write( "ANSWER: 70 adult tickets, 220 student tickets. \n" ); document.write( "CHECK: 70(8)+220(4) = 560+880 = 1440 \n" ); document.write( "Informally -- if an algebraic solution is not required.... \n" ); document.write( "(1) If all 290 tickets had been student tickets, the total cost would have been $290*4 = $1160; the actual total is $1440-$1160 = $280 more than that. \n" ); document.write( "(2) The difference between the cost of an adult ticket and a student ticket is $4. \n" ); document.write( "(3) The number of adult tickets needed to make up that extra $280 is 280/4 = 70. \n" ); document.write( "ANSWER: 70 adult tickets and 220 student tickets \n" ); document.write( "Note that the informal solution used exactly the same calculations as the formal method.... \n" ); document.write( " \n" ); document.write( " |