document.write( "Question 106723This question is from textbook Algebra, structure and meathod, book 1
\n" ); document.write( ": Transforming Formulas
\n" ); document.write( "page 166, number 25\r
\n" ); document.write( "\n" ); document.write( "solve the given formula for the variable shown. state the restrictions, if any, for the formula obtained to be meaningful.\r
\n" ); document.write( "\n" ); document.write( "a=180(n-2)all over n; solve for n\r
\n" ); document.write( "\n" ); document.write( "the answer is;
\n" ); document.write( "n=360 all over 180-a; a does not = 0
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Algebra.Com's Answer #77662 by Earlsdon(6294)\"\" \"About 
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Your answer is correct but the restriction on a doesn't make sense.
\n" ); document.write( "In the formula: \"n+=+360%2F%28180-a%29\", if a were zero, you still have a valid formula of \"n+=+360%2F180\" or \"n+=+2\"
\n" ); document.write( "What you really should be concerned with in a formula that has a denominator is, what would make the denominator equal to zero. And the answer here is a = 180.
\n" ); document.write( "If a were equal to 180, then you would have: \"n+=+360%2F%28180-180%29\" or \"n+=+360%2F0\" and, as you know, division by zero is not defined.
\n" ); document.write( "So the restriction is: a cannot equal 180
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