document.write( "Question 1154210: A train moving at 12 m/s accelerates to 36 m/s over a distance of 8.0 km. (A) what is the train's acceleration? (B) how much time does it take the train to reach 36 m/s? (C) what is the average velocity of the train?
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Algebra.Com's Answer #776606 by mananth(16946)\"\" \"About 
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v=36
\n" ); document.write( "u=12
\n" ); document.write( "s=8000\r
\n" ); document.write( "\n" ); document.write( "v^2-u^2=2as\r
\n" ); document.write( "\n" ); document.write( "1152 =2*a*8000\r
\n" ); document.write( "\n" ); document.write( "1152/16000= 0.072 m/s^2
\n" ); document.write( "a=0.072m/s^2\r
\n" ); document.write( "\n" ); document.write( "v=u+at, v=36\r
\n" ); document.write( "\n" ); document.write( "36= 12 +0.072 t\r
\n" ); document.write( "\n" ); document.write( "24/0.072 = t\r
\n" ); document.write( "\n" ); document.write( "time taken = 333.33 s\r
\n" ); document.write( "\n" ); document.write( "Average velocity = (u+v)/2
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