document.write( "Question 1154210: A train moving at 12 m/s accelerates to 36 m/s over a distance of 8.0 km. (A) what is the train's acceleration? (B) how much time does it take the train to reach 36 m/s? (C) what is the average velocity of the train?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #776606 by mananth(16946)![]() ![]() You can put this solution on YOUR website! v=36 \n" ); document.write( "u=12 \n" ); document.write( "s=8000\r \n" ); document.write( "\n" ); document.write( "v^2-u^2=2as\r \n" ); document.write( "\n" ); document.write( "1152 =2*a*8000\r \n" ); document.write( "\n" ); document.write( "1152/16000= 0.072 m/s^2 \n" ); document.write( "a=0.072m/s^2\r \n" ); document.write( "\n" ); document.write( "v=u+at, v=36\r \n" ); document.write( "\n" ); document.write( "36= 12 +0.072 t\r \n" ); document.write( "\n" ); document.write( "24/0.072 = t\r \n" ); document.write( "\n" ); document.write( "time taken = 333.33 s\r \n" ); document.write( "\n" ); document.write( "Average velocity = (u+v)/2 \n" ); document.write( " |