document.write( "Question 1154202: Pls help!!! I’m desperate!!!\r
\n" ); document.write( "\n" ); document.write( "The equation of the perpendicular bisector of the line segment joining the points $(-3,8)$ and $(-5,4)$ is $y = mx + b$. Find $m+b$.\r
\n" ); document.write( "\n" ); document.write( "Note: The perpendicular bisector of the line segment $\overline{AB}$ is the line that passes through the midpoint of $\overline{AB}$ and is perpendicular to $\overline{AB}$.\r
\n" ); document.write( "\n" ); document.write( "Thank you!!!
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Algebra.Com's Answer #776599 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "D is the mid of BC\r
\n" ); document.write( "\n" ); document.write( "D(x1,y1) \r
\n" ); document.write( "\n" ); document.write( "x1= (-3-5)/2 =-4\r
\n" ); document.write( "\n" ); document.write( "y1= (8+4)/2 =6\r
\n" ); document.write( "\n" ); document.write( "slope of BC = (8-4)/(-3+5)= 2\r
\n" ); document.write( "\n" ); document.write( "Slope of AD = 1/2 ( it is perpendicular to BC)\r
\n" ); document.write( "\n" ); document.write( "Equation of AD = (y-y1)=m(x-x1)
\n" ); document.write( "(y-6)=1/2 * (x+4)
\n" ); document.write( "2y-12= x+4
\n" ); document.write( "2y = x+16
\n" ); document.write( "y= 1/2*x+8\r
\n" ); document.write( "\n" ); document.write( "compare with y= mx+b\r
\n" ); document.write( "\n" ); document.write( "m=1/2 and b =8\r
\n" ); document.write( "\n" ); document.write( "m+b = 1/2 +8\r
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