document.write( "Question 1154197: A chemical company makes two brands of antifreeze. The first brand is 45% pure antifreeze, and the second brand is 85% pure antifreeze. In order to obtain 40 gallons of a mixture that contains 75% pure antifreeze, how many gallons of each brand of antifreeze must be used? \n" ); document.write( "
Algebra.Com's Answer #776589 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = gallons of 45% antifreeze needed
\n" ); document.write( "Let \"+b+\" = gallons of 85% antifreeze needed
\n" ); document.write( "----------------------------------------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+40+\"
\n" ); document.write( "(2) \"+%28+.45a+%2B+.85b+%29+%2F+40+=+.75+\"
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "(2) \"+.45a+%2B+.85b+=+30+\"
\n" ); document.write( "(2) \"+45a+%2B+85b+=+3000+\"
\n" ); document.write( "(2) \"+9a+%2B+17b+=+600+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "Multiply both sides of (1) by \"9\" and
\n" ); document.write( "subtract (1) from (2)
\n" ); document.write( "(2) \"+9a+%2B+17b+=+600+\"
\n" ); document.write( "(1) \"+-9a+-+9b+=+-360+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "\"+8b+=+240+\"
\n" ); document.write( "\"+b+=+30+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+30+=+40+\"
\n" ); document.write( "(1) \"+a+=+10+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "10 gallons of 45% antifreeze are needed
\n" ); document.write( "30 gallons of 85% antifreeze are needed
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.45a+%2B+.85b+%29+%2F+40+=+.75+\"
\n" ); document.write( "(2) \"+%28+.45%2A10+%2B+.85%2A30+%29+%2F+40+=+.75+\"
\n" ); document.write( "(2) \"+%28+4.5+%2B+25.5+%29+%2F+40+=+.75+\"
\n" ); document.write( "(2) \"+4.5+%2B+25.5+=+30+\"
\n" ); document.write( "(2) \"+30+=+30+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );