document.write( "Question 1154192: How many liters of 10% acid solution must be added to a 40% acid solution to produce an 8 liters volume 30% acid solution \n" ); document.write( "

Algebra.Com's Answer #776579 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Here is a quick and easy way (if you understand it!) to solve two-part mixture problems like this.

\n" ); document.write( "(1) 30% is \"twice as close\" to 40% as it is to 10%. (The difference between 40 and 30 is half the difference between 30 and 10.)

\n" ); document.write( "(2) That means the mixture needs to use twice as much of the 40% acid as the 10% acid.

\n" ); document.write( "(3) Twice as much means 2/3 of the mixture needs to be the 40% acid, so 1/3 is the 10% acid.

\n" ); document.write( "ANSWER: 2/3 of 8 liters, or 16/3 liters, of 40% acid; 1/3 of 8 liters, or 8/3 liters, of 10% acid.

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