document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106700>Question 106700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, my son asked me some questions on algebra but i myself was confused. hope u can help me to help him with these.write these follwing expressions in the simplest form:\r<BR>\n" );
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document.write( "1. b+7+2b+10<BR>\n" );
document.write( "2. (3d+5)+(d-2)<BR>\n" );
document.write( "3. 3m-(-m) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77657 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify:<BR>\n" );
document.write( "1.  b+7+2b+10  Add the like-terms together. The like-terms are: b & 2b and 7 & 10. So we get:<BR>\n" );
document.write( "(b+2b) + (7+10)  after adding, we have:<BR>\n" );
document.write( "3b+17\r<BR>\n" );
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document.write( "2.  (3d+5)-(2d-5) Again, add together the like-terms which are: 3d & -2d and 5 & +5  Notice the change in sign (From - to +) on the last 5 after you remove the parentheses. 3d+5-2d+5<BR>\n" );
document.write( "(3d-2d) + (5+5) = d+10\r<BR>\n" );
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document.write( "3.  3m-(-m) Remember that to subtract a number you add its opposite (same number but opposite sign).<BR>\n" );
document.write( "3m+m = 4m </SPAN>\n" );
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