document.write( "Question 1154168: y=2x+1
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Algebra.Com's Answer #776550 by ikleyn(52790) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " When you have such a system, a standard mantra to pronounce is THIS:\r
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document.write( "Left sides are identical,  hence, the right sides are equal, which gives you an equation\r\n" );
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document.write( "        2x + 1 = -4x + 7.\r\n" );
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document.write( "Simplify step by step and solve for x\r\n" );
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document.write( "        2x + 4x = 7 - 1\r\n" );
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document.write( "        6x      = 6\r\n" );
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document.write( "         x      = 6/6 = 1.\r\n" );
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document.write( "Thus you just found \"x\".  It is 1.\r\n" );
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document.write( "Now substitute the found value of \"x\" into any of the two original equations to find \"y\".\r\n" );
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document.write( "From the first equation,   y = 2x + 1 = 2*1 + 1 = 3.\r\n" );
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document.write( "ANSWER.  The solution to the system is  x= 1,  y= 3.\r\n" );
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document.write( "CHECK.  Make checking on your own by substituting the found values x and y into original equations.\r\n" );
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document.write( "        I leave it to you  ---- it is necessary part of the solution (!)\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is a kind of the Substitution method.\r
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\n" ); document.write( "\n" ); document.write( "When you are offered equation in this form, you are lucky: the equations are just ready for substitution.\r
\n" ); document.write( "\n" ); document.write( "It facilitates the remaining work.\r
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