document.write( "Question 1154150: We select three balls randomly (one after another) of a box contains 1 white, 2 yellow and 3 blue balls. If all balls have the same chance of selecting, then:
\n" ); document.write( "a) What is the probability that the selected balls have the same color ?
\n" ); document.write( "b) What is the probability that no white balls have been selected ?
\n" ); document.write( "c) What is the probability that all [BOTH] yellow balls are selected ?
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Algebra.Com's Answer #776539 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "For each case, consider the probabilities that each ball drawn in succession satisfies the condition.

\n" ); document.write( "a) If all three balls are the same color, they must all be blue.

\n" ); document.write( "P(all the same) = P(all blue) = \"%283%2F6%29%282%2F5%29%281%2F4%29+=+6%2F120+=+1%2F20+=+0.05\"

\n" ); document.write( "b) If none of the three is white, then they must all be yellow or blue.

\n" ); document.write( "P(no white) = \"%285%2F6%29%284%2F5%29%283%2F4%29+=+60%2F120+=+1%2F2+=+.50\"

\n" ); document.write( "c) (NOTE: I interpret \"all yellow balls selected\" as meaning ONLY yellow balls are selected. Another tutor has interpreted it to mean BOTH of the 2 yellow balls (and one other) are selected. Both interpretations are valid.)

\n" ); document.write( "There are only 2 yellow; all three selected can't be yellow.

\n" ); document.write( "P(all yellow) = \"%282%2F6%29%281%2F5%29%280%2F4%29+=+0%2F120+=+0\"

\n" ); document.write( "Note the first two problems can also be solved using more advanced techniques. They are overkill for simple problems like this; but you should know how to use them.

\n" ); document.write( "(a) We are choosing 3 of the 6 balls, and we need to choose all 3 of the blue balls and none of the others:

\n" ); document.write( "P(3 blue) =

\n" ); document.write( "(b) We are again choosing 3 of the 6 balls, and we need to choose 3 of the 5 blue or yellow balls and 0 of the1 white:

\n" ); document.write( "P(no white) = \"%28C%285%2C3%29%2AC%281%2C0%29%29%2FC%286%2C3%29+=+%2810%2A1%29%2F20+=+1%2F2\"

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