document.write( "Question 1154150: We select three balls randomly (one after another) of a box contains 1 white, 2 yellow and 3 blue balls. If all balls have the same chance of selecting, then:
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Algebra.Com's Answer #776538 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "In this problem, the probability is the ratio/fraction, whose denominator is the same for all 3 parts, a), b) and c).\r\n" );
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document.write( "This denominator is   =  = 20, and it represents the number of triples that can be formed from 6 = 1+2+3 balls.\r\n" );
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document.write( "The numerator is different for each part. It is the number of favorable triples in each case.\r\n" );
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document.write( "(a)  In this case, there is only one favorable triple, consisting of 3 blue balls.\r\n" );
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document.write( "     Thus the probability in this case is  P =  = 0.05.\r\n" );
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document.write( "(b)  In this case, favorable triples can be formed from  5 = 2+3 yellow and blue balls.\r\n" );
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document.write( "     The number of favorable triples is, therefore,   = 10.\r\n" );
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document.write( "     Thus the probability in this case is  P =  =  = 0.5.\r\n" );
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document.write( "(c)  This time the triples contain 2 yellow balls, and we can add EITHER 1 white or any one of 3 blue balls.\r\n" );
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document.write( "     Hence, the number of different favorable triples in this case is  1+3 = 4.\r\n" );
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document.write( "     Therefore,  the probability is  P =  =  = 0.2.\r\n" );
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