document.write( "Question 1154151: Find three consecutive positive odd integers such that the sum of their squares is 371. \n" ); document.write( "

Algebra.Com's Answer #776524 by mananth(16946) $\"\"$ $\"About$

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Find three consecutive positive odd integers such that the sum of their squares is 371.\r
\n" ); document.write( "\n" ); document.write( "let n be the first positive odd integer\r
\n" ); document.write( "\n" ); document.write( "second will be n+2\r
\n" ); document.write( "\n" ); document.write( "Third will be n+4\r
\n" ); document.write( "\n" ); document.write( "n^2 +(n+2)^2 +(n+4)^2=371\r
\n" ); document.write( "\n" ); document.write( "n^2 +n^2 +4n +4 + n^2 +8n +16=371\r
\n" ); document.write( "\n" ); document.write( "3n^2+12n + 20=371\r
\n" ); document.write( "\n" ); document.write( "3n^2+12n-351=0\r
\n" ); document.write( "\n" ); document.write( "divide by 3\r
\n" ); document.write( "\n" ); document.write( "n^2+4n-117=0\r
\n" ); document.write( "\n" ); document.write( "(n+13)(n-9)=0\r
\n" ); document.write( "\n" ); document.write( "n=-13 Or n=9\r
\n" ); document.write( "\n" ); document.write( "but n is positive\r
\n" ); document.write( "\n" ); document.write( "Therefore n=9\r
\n" ); document.write( "\n" ); document.write( "The numbers are 9,11,13\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "9^2+11^2+13^2=371\r
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