document.write( "Question 1154151: Find three consecutive positive odd integers such that the sum of their squares is 371. \n" ); document.write( "
Algebra.Com's Answer #776523 by ramkikk66(644)\"\" \"About 
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Let the 3 odd integers be x - 2, x and x + 2
\n" ); document.write( "Square of the 1st = \"x%5E2+-+4x+%2B+4\"
\n" ); document.write( "Square of the 2nd = \"x%5E2\"
\n" ); document.write( "Square of the 3rd = \"x%5E2+%2B+4x+%2B+4\"
\n" ); document.write( "Adding the 3 equations above, and equating to the given sum, we get
\n" ); document.write( "\"3x%5E2+%2B+8+=+371\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2+=+371+-+8+=+363\"
\n" ); document.write( "\"x%5E2+=+363%2F3+=+121\"\r
\n" ); document.write( "\n" ); document.write( "So \"x+=+sqrt%28121%29+=+11\"
\n" ); document.write( "since it is given that x is positive, it cannot be -11\r
\n" ); document.write( "\n" ); document.write( "So the 3 numbers are \"9\", \"11\" and \"13\".\r
\n" ); document.write( "\n" ); document.write( "Check by adding the 3 squares
\n" ); document.write( "\"9%5E2+%2B+11%5E2+%2B+13%5E2+=+81+%2B+121+%2B+169+=+371\". Checked!\r
\n" ); document.write( "\n" ); document.write( "Ans: 9, 11, 13
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