.
\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Let x be the very central point for the given 4 terms of the AP.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "In other words, let x be the average of the 4 terms of the AP\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " x =
.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Next, let d be the common difference of the AP.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Our goal is to find \"x\" and \"d\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is clear that \r\n" );
document.write( "\r\n" );
document.write( "
= x - 1.5d;\r\n" );
document.write( "\r\n" );
document.write( "
= x - 0.5d;\r\n" );
document.write( "\r\n" );
document.write( "
= x + 0.5d;\r\n" );
document.write( "\r\n" );
document.write( "
= x + 1.5d.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Therefore,
+
= 2x.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It implies 2x = 8, and hence x = 4.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Also,
= 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It implies (x-0.5d)*(x+0.5d) = 15, or\r\n" );
document.write( "\r\n" );
document.write( " x^2 - 0.25d^2 = 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Substitute here x= 4 to get\r\n" );
document.write( "\r\n" );
document.write( " 0.25d^2 = 4^2 - 15 = 16 - 15 = 1.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Thus d^2 =
= 4; hence, d =
= +/- 2.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The problem is just solved. We know the central point x = 4 and the common difference d = +/-2.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "If d = 2, then
= 4-1.5*2 = 1;
= 1+2 = 3;
= 3+2 = 5, and
= 5 + 2 = 7.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "If d = -2, then we have the same sequence in the REVERSED order:
= 7;
= 5;
= 3 and
= 1.\r\n" );
document.write( "
\r
\n" );
document.write( "\n" );
document.write( "Solved.\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "