document.write( "Question 106691: A rectangular corral built with 190 m of fencing that inludes four separate grazing areas lies on a 962 m(square) rectangular plot of land. the fence that divides the grazing areas is parallel to two of the sides of the corral. if there is a 1 m strip of land between each side of the corral and the property line, find the dimesions of the corral. there may be more than one answer!!... \n" ); document.write( "
Algebra.Com's Answer #77647 by edjones(8007)![]() ![]() You can put this solution on YOUR website! L*w=A \n" ); document.write( "2L+2w=P \n" ); document.write( ". \n" ); document.write( "L*w=926 \n" ); document.write( "Our 2nd formula uses the perimeter formula plus the extra fencing to divide the corral in quarters. We have to use 3 instead of 2 for the coeficients of L and w because of the extra fencing to divide the coral into 4ths. we also have to subtract 2 from L and w to account for the 1 m strip of land not used for the corral \n" ); document.write( "3(L-2)+3(w-2)=190 \n" ); document.write( "3L-6+3w-6=190 \n" ); document.write( "3L+3w-12=190 \n" ); document.write( "3L+3w=190+12 \n" ); document.write( "3L+3w=202 \n" ); document.write( ". \n" ); document.write( "A) L*w=926 \n" ); document.write( "B) 3L+3w=202 \n" ); document.write( ". \n" ); document.write( "L=926/w \n" ); document.write( "3(926/w)+3w=202 substitute 926/w for L \n" ); document.write( "2778/w+3w=202 \n" ); document.write( "2778+3w^2=202w multiply each side by w to eliminate the fraction. \n" ); document.write( "3w^2-202w+2778=0 \n" ); document.write( "Quadratic Formula (see below): w=19.26 m, w= 48.06 \n" ); document.write( "I made L= 48.06 m and w= 19.26 m \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |