document.write( "Question 106699: The sum of two numbers is 94. The second is 6 more than 3 times the first. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #77646 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The sum of two numbers is \"94\".
\n" ); document.write( "let numbers be \"x\" and \"y\", then:
\n" ); document.write( "\"x%2By+=+94\" \r
\n" ); document.write( "\n" ); document.write( "if the second is \"6\" more than \"3\" times the first, we have:\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+6+=+y\"\r
\n" ); document.write( "\n" ); document.write( "then, we can substitute this in equatation above:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+94\"\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+3x+%2B+6+=+94\"\r
\n" ); document.write( "\n" ); document.write( "\"4x+%2B+6+=+94\"......add \"-6\" to both sides\r
\n" ); document.write( "\n" ); document.write( "\"4x+%2B6+-%286%29+=+94+-+%286%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4x+=+88\" ..divide both sides by \"4\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+22\" ........ first number\r
\n" ); document.write( "\n" ); document.write( "\"y+=+3x+%2B+6\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+3%2A22+%2B+6\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+66+%2B+6\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+72\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"22+%2B+72+=+94\"\r
\n" ); document.write( "\n" ); document.write( "\"94+=+94\"
\n" ); document.write( "
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