document.write( "Question 1154081: Mary is now four times as old as her daughter. Four years ago,the product of their ages was 40. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #776442 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Mary is now four times as old as her daughter. Four years ago,the product of their ages was 40. Find their present ages.\r
\n" ); document.write( "\n" ); document.write( "If daughter is x
\n" ); document.write( "Mother's age = 4x\r
\n" ); document.write( "\n" ); document.write( "4 years ago
\n" ); document.write( "daughter's age = x-4
\n" ); document.write( "Mother's age = 4x-4\r
\n" ); document.write( "\n" ); document.write( "Product of ages (x-4)((4x-4)\r
\n" ); document.write( "\n" ); document.write( "(x-4)((4x-4)=40\r
\n" ); document.write( "\n" ); document.write( "expand\r
\n" ); document.write( "\n" ); document.write( "4x^2-4x-16x+16 =40\r
\n" ); document.write( "\n" ); document.write( "4x^2-20x-24=0\r
\n" ); document.write( "\n" ); document.write( "x^2-5x-6=0\r
\n" ); document.write( "\n" ); document.write( "x^2-6x+x-6=0\r
\n" ); document.write( "\n" ); document.write( "x(x-6)+1(x-6)=0\r
\n" ); document.write( "\n" ); document.write( "(x-6)(x+1)=0\r
\n" ); document.write( "\n" ); document.write( "x=6 or -1\r
\n" ); document.write( "\n" ); document.write( "age cannot be negative
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "continue
\n" ); document.write( "
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