document.write( "Question 1154064: the sides of a triangle are (x+2), (3x+1) and (x+7) units. find the units of x if the perimeter of the triangle is 140 units
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Algebra.Com's Answer #776425 by ikleyn(52786) $\"\"$ $\"About$

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\n" ); document.write( "the sides of a triangle are (x+2), (3x+1) and (x+7) units. find the units of x if the perimeter of the triangle is 140 units
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document.write( "Your equation is\r\n" );
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document.write( "    (x+2) + (3x+1) + (x+7) = 140.\r\n" );
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document.write( "Simplify and solve for x.\r\n" );
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document.write( "    5x = 140 - 2 - 1 - 7 = 130.\r\n" );
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document.write( "     x = 130/5 = 26.\r\n" );
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document.write( "The sides are  (26+2) = 28;  3*26+1 = 79;  26+7 = 33.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Since 79 > 28 + 33, the thriangle inequality is V I O L A T E D, which means that\r
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SUCH A TRIANGLE DOES NOT EXIST.

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