document.write( "Question 1154019: Find the inverse of the following function \r
\n" ); document.write( "\n" ); document.write( "g(x) = e^x -2e^x / 2 \n" ); document.write( "

Algebra.Com's Answer #776398 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"g%28x%29+=+%28e%5Ex+-2e%5Ex%29+%2F+2\"$ inverse\r
\n" ); document.write( "\n" ); document.write( " $\"g%28x%29+=+y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=+%28e%5Ex+-2e%5Ex%29+%2F+2\"$ .........swap variables\r
\n" ); document.write( "\n" ); document.write( " $\"x=+%28e%5Ey+-2e%5Ey%29+%2F+2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x=+e%5Ey+-2e%5Ey\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2x=+-e%5Ey\"$ .......switch sides\r
\n" ); document.write( "\n" ); document.write( " $\"e%5Ey=+-2x\"$ ......take log of both sides\r
\n" ); document.write( "\n" ); document.write( " $\"ln%28e%5Ey%29=+ln%28-2x%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y%2Aln%28e%29=+ln%28-2x%29\"$ ........... $\"ln%28e%29=1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=+ln%28-2x%29\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"+g%5E-1%28x%29+=ln%28-2x%29\"$ \r
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