document.write( "Question 1154014: How many gallons of 20% alcohol solution and 45% alcohol solution must be mixed to get 10 gallons of 25% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #776393 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "...and I prefer to solve this kind of problem using 0 variables....

\n" ); document.write( "Here is the quick and easy solution to this problem:

\n" ); document.write( "(1) The target 25% is 1/5 of the way from 20% to 45%. (20 to 45 is a difference of 25; 20 to 25 is a difference of 5; 5/25 = 1/5)
\n" ); document.write( "(2) That means 1/5 of the mixture has to be the 45% ingredient.

\n" ); document.write( "ANSWER: 1/5 of 10 gallons, or 2 gallons, of the 45% alcohol solution; 10-2=8 gallons of the 20% alcohol solution.

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