document.write( "Question 1154014: How many gallons of 20% alcohol solution and 45% alcohol solution must be mixed to get 10 gallons of 25% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #776386 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "How many gallons of 20% alcohol solution and 45% alcohol solution must be mixed to get 10 gallons of 25% alcohol solution?
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I STRONGLY believe that these types of problems, when possible, need to be solved using ONLY 1 variable.
\n" ); document.write( "For one, they're less confusing, and 2) much, much less time-consuming.\r
\n" ); document.write( "\n" ); document.write( "Let the amount of 20% alcohol to mix be T
\n" ); document.write( "Then amount of 45% alcohol to mix = 10 - T
\n" ); document.write( "We then get: .2T + .45(10 - T) = .25(10)
\n" ); document.write( ".2T + 4.5 - .45T = 2.5
\n" ); document.write( ".2T - .45T = 2.5 - 4.5
\n" ); document.write( "- .25T = - 2
\n" ); document.write( "T, or \n" ); document.write( "
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