document.write( "Question 1154026: rowing with a current keith rowed a canoe 3 miles an hour. on his return trip against the current keith take 1.5hours. how fast does keith row in still water and how fast is the current \n" ); document.write( "
Algebra.Com's Answer #776377 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
Let current speed be x mph
\n" ); document.write( "Let keith's speed in still water be y mph\r
\n" ); document.write( "\n" ); document.write( "Distance travelled in 1 hour = 3 miles
\n" ); document.write( "Travelling with current, effective speed is (y + x) mph
\n" ); document.write( "So the distance travelled = speed * time
\n" ); document.write( "= (y + x) * 1 = (y + x) = 3
\n" ); document.write( "Travelling against current, his effective speed is (y - x) mph
\n" ); document.write( "At (y - x) mph, he took 1.5 hours for the same distance i.e. 3 miles\r
\n" ); document.write( "\n" ); document.write( "Since speed * time = distance, we get the equation\r
\n" ); document.write( "\n" ); document.write( "(y - x) * 1.5 = y + x = 3
\n" ); document.write( "Which can be broken up as 2 equations in x and y as below\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+3\" --- (1)
\n" ); document.write( "\"1.5y+-+1.5x+=+3\" --- (2)\r
\n" ); document.write( "\n" ); document.write( "Multiplying (1) by 1.5
\n" ); document.write( "\"1.5x+%2B+1.5y+=+4.5\" --- (3)\r
\n" ); document.write( "\n" ); document.write( "Adding (2) and (3)
\n" ); document.write( "\"3y+=+7.5\"\r
\n" ); document.write( "\n" ); document.write( "i.e.
\n" ); document.write( "\"y+=+2.5\"
\n" ); document.write( "\"x+=+3+-+y+=+0.5\"\r
\n" ); document.write( "\n" ); document.write( "Speed in still water = 2.5 mph
\n" ); document.write( "Speed of current = 0.5 mph\r
\n" ); document.write( "\n" ); document.write( "Check.
\n" ); document.write( "With current, effective speed = 2.5 + 0.5 = 3 mph, so time taken to travel 3 miles = 3 / 3 = 1 hour (check)
\n" ); document.write( "Against current, effective speed = 2.5 - 0.5 = 2 mph, so time taken to travel 3 miles = 3 / 2 = 1.5 hours (check)\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!
\n" ); document.write( "
\n" ); document.write( "
\n" );