document.write( "Question 1154027: Hi
\n" ); document.write( "There are 4 red balls 6 green balls and 5 yellow balls. Jane picks a ball at random without replacement. Find the probability that\r
\n" ); document.write( "\n" ); document.write( "A red ball is picked\r
\n" ); document.write( "\n" ); document.write( "A yellow ball is not picked. \r
\n" ); document.write( "\n" ); document.write( "Thanks \n" ); document.write( "

Algebra.Com's Answer #776375 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!
P(red) = (# of red) / (total # of balls) = 4/(4+6+5) = $\"+highlight%28+4%2F15+%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "P(not yellow) = P(red or green) / (total #) = (4+6)/(4+6+5) = 10/15 = $\"+highlight%282%2F3%29\"$ --OR-- you can say P(not yellow) = 1 - P(yellow) = 1 - (5/15) = 10/15 = 2/3 \n" ); document.write( "

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