document.write( "Question 1154010: The larger of two numbers is 1 more than 3 times the smaller. If the smaller is subtracted from the larger, the result is 13. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #776370 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "Make x = larger number
\n" ); document.write( "Make y = smaller number
\n" ); document.write( "x + 1 = 3y............Eq(1)
\n" ); document.write( "x - y = 13............Eq(2)
\n" ); document.write( "Rearranging Eq(1)
\n" ); document.write( "x + 1 = 3y
\n" ); document.write( "x = 3y - 1
\n" ); document.write( "Substitute back into Eq(2)
\n" ); document.write( "x - y = 13
\n" ); document.write( "3y - 1 - y = 13
\n" ); document.write( "Collect like terms
\n" ); document.write( "2y - 1 = 13
\n" ); document.write( "2y = 14
\n" ); document.write( "y = 7
\n" ); document.write( "Substitute y = 7 into Eq(2)
\n" ); document.write( "x - y = 13
\n" ); document.write( "x - 7 = 13
\n" ); document.write( "x = 20
\n" ); document.write( "Larger number = 20
\n" ); document.write( "Smaller number = 7
\n" ); document.write( "Hope this helps :-)
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