document.write( "Question 1154013: Mr. Jones has $16,000 to invest. He invests part at 9% and the rest at 10%. If he earns $1,510 in interest after 1 year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #776367 by ramkikk66(644)![]() ![]() ![]() You can put this solution on YOUR website! Total money = 16000\r \n" ); document.write( "\n" ); document.write( "Let x dollars be invested at 9%. So 16000 - x dollars would be invested at 10%.\r \n" ); document.write( "\n" ); document.write( "Interest on the 1st part = x * 0.09 \n" ); document.write( "Interest on the 2nd part = (16000 - x) * 0.1\r \n" ); document.write( "\n" ); document.write( "Total interest = 1510 (given)\r \n" ); document.write( "\n" ); document.write( "i.e. \n" ); document.write( "expanding \n" ); document.write( " \n" ); document.write( "moving variables and constants to either side of the equation \n" ); document.write( " \n" ); document.write( "i.e \n" ); document.write( "\n" ); document.write( "Amount invested at 9% = 9000, interest earned = 9000 * 0.09 = 810 \n" ); document.write( "Amount invested at 10% = 16000 - 9000 = 7000, interest earned = 7000 * 0.1 = 700\r \n" ); document.write( "\n" ); document.write( "Total interest = 810 + 700 = 1510, check!\r \n" ); document.write( "\n" ); document.write( "Ans: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |