document.write( "Question 1154013: Mr. Jones has $16,000 to invest. He invests part at 9% and the rest at 10%. If he earns $1,510 in interest after 1 year, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #776366 by mananth(16946)\"\" \"About 
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Investment I 9.00% per annum $x
\n" ); document.write( " Investment II 10.00% per annum $y
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\n" ); document.write( " x + y 16000 ------------------------1
\n" ); document.write( " 9.00% x + 10.00% y = 1510
\n" ); document.write( " Multiply by 100
\n" ); document.write( " 9 x + 10 y = 151000 --------2
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\n" ); document.write( " Multiply (1) by -10
\n" ); document.write( " we get
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\n" ); document.write( " -10 x -10 y = -160000.00
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\n" ); document.write( " Add this to (2)
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\n" ); document.write( " -1 x+ 0 y = -9000.00
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\n" ); document.write( " divide by -1
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\n" ); document.write( " x = 9000 investment at 9%
\n" ); document.write( " Balance 7000 investment at 10%
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\n" ); document.write( "\n" ); document.write( "CHECK Interest
\n" ); document.write( " 9000 810
\n" ); document.write( " 7000 700
\n" ); document.write( " Total 1510
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